The four quantum numbers for the valence shell electron of Sodium $(Z=11)$ are:

  • A
    $n=2, \ell=1, m=-1, s=-\frac{1}{2}$
  • B
    $n=3, \ell=0, m=0, s=+\frac{1}{2}$
  • C
    $n=3, \ell=2, m=-2, s=-\frac{1}{2}$
  • D
    $n=3, \ell=2, m=2, s=+\frac{1}{2}$

Explore More

Similar Questions

What is the number of radial nodes in the $2s$ orbital?

If $Br^{-}$ configuration is $[Ar]\, 3d^{10}\,4s^2\,4p^6$,then $Br^{+2}$ configuration will be identical to which element?

Difficult
View Solution

The correct set of quantum numbers for the unpaired electron of a chlorine atom is:

Describe the orbitals with the following quantum numbers using $s, p, d, f$ notation:
$(a) n = 1, l = 0$
$(b) n = 3, l = 1$
$(c) n = 4, l = 2$
$(d) n = 4, l = 3$

While filling up of electrons in the atomic orbitals,the $4s$ orbital is filled before the $3d$ orbital,but the reverse happens during the ionization of the atom. Explain why?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo