The freezing point of heavy water at $1 \ atm$ pressure is: (in $^{\circ}C$)
- A$0$
- B$3.8$
- C$4.8$
- D$1$
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Assertion $(A)$ : $NaCl$ is less soluble in heavy water than in ordinary water.
Reason $(R)$ : Dielectric constant of ordinary water is more than that of heavy water.
The correct answer is
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