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(A) According to the Clausius-Clapeyron equation,the change in freezing point with pressure is given by $\frac{dT}{dP} = \frac{T(V_2 - V_1)}{L}$,where

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Expands while freezing

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(A) According to the Clausius-Clapeyron equation,the change in freezing point with pressure is given by $\frac{dT}{dP} = \frac{T(V_2 - V_1)}{L}$,where $T$ is the temperature,$V_2$ and $V_1$ are the volumes of the solid and liquid phases respectively,and $L$ is the latent heat of fusion.If the freezing point decreases with an increase in pressure,then $\frac{dT}{dP} Since $T$ and $L$ are positive,this implies that $(V_2 - V_1) This indicates that the volume of the solid is less than the volume of the liquid,meaning the substance expands upon melting or contracts upon freezing.However,for substances like water,which expand upon freezing $(V_{solid} > V_{liquid})$,the freezing point decreases with increasing pressure.Therefore,the correct condition is that the liquid expands while freezing.

List-$I$	List-$II$
$A$. When ice melts into water	$I$. Volume increases
$B$. When water changes into steam	$II$. Volume decreases
$C$. Melting point of ice	$III$. Increases with increase of pressure
$D$. Boiling point of water	$IV$. Decreases with increase in pressure

The freezing point of a liquid decreases when pressure is increased,if the liquid:

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