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(B) The maximum kinetic energy $(K_{max})$ of photoelectrons is given by Einstein's photoelectric equation: $K_{max} = h
u - \phi$,where $h$ is Planc

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increase the maximum kinetic energy of the photoelectrons and would increase the photoelectric current by a factor of two.

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(B) The maximum kinetic energy $(K_{max})$ of photoelectrons is given by Einstein's photoelectric equation: $K_{max} = h
u - \phi$,where $h$ is Planck's constant,$
u$ is the frequency of incident light,and $\phi$ is the work function of the material.When the frequency $
u$ is doubled,the term $h
u$ increases,which leads to an increase in $K_{max}$. However,$K_{max}$ does not simply double because of the subtraction of the constant work function $\phi$.The photoelectric current is directly proportional to the intensity of the incident light. When the intensity is doubled,the number of incident photons per unit time doubles,which in turn doubles the number of photoelectrons emitted per unit time,thereby doubling the photoelectric current.Therefore,the correct description is that the kinetic energy increases (but not necessarily by a factor of two) and the photoelectric current increases by a factor of two. Among the given options,option $B$ is the most appropriate description of the physical phenomena.

The frequency and the intensity of a beam of light falling on the surface of a photoelectric material are both increased by a factor of two. This will:

Similar Questions

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