The frequency of $AC$ mains in India is (in $\text{ Hz}$)

The peak voltage of the $ac$ source is equal to:

In an $ac$ circuit,the instantaneous voltage $e(t)$ and current $i(t)$ are given by $e(t) = 5[\cos \omega t + \sqrt{3} \sin \omega t] \ V$ and $i(t) = 5[\sin(\omega t + \frac{\pi}{4})] \ A$. Determine the phase relationship between voltage and current.

$A$ $40 \ \Omega$ electric heater is connected to a $200 \ V, 50 \ Hz$ mains supply. The peak value of electric current flowing in the circuit is approximately......$A$

$A$ generator produces a voltage that is given by $V = 240 \sin(120t)$,where $t$ is in seconds. The frequency and $r.m.s.$ voltage are:

If the instantaneous current is given by $i = 4 \cos(\omega t + \phi)$ amperes,then the $r.m.s.$ value of the current is: