The frequency of a stretched uniform wire of length $L$ under tension is in resonance with the fundamental frequency of a closed pipe of same length. If the tension in the wire is increased by $8 \ N$,it is in resonance with the first overtone of the same closed pipe. The initial tension in the wire is (in $N$)

$A$ hollow pipe of length $0.8 \ m$ is closed at one end. At its open end,a $0.8 \ m$ long uniform string is vibrating in its second harmonic and it resonates with the fundamental frequency of the pipe. If the tension in the string is $50 \ N$ and the speed of sound in air is $320 \ m/s$,the mass of the string is: (in $g$)

$A$ pipe open at one end has a length of $0.8 \text{ m}$. At the open end of the tube, a string $0.5 \text{ m}$ long is vibrating in its first overtone and resonates with the fundamental frequency of the pipe. If the tension in the string is $50 \text{ N}$, what is the mass of the string (in $\text{ g}$)? (Neglect end correction, Speed of sound = $320 \text{ m/s}$)

Diffraction of sound waves is more evident than light waves in daily life because:

$A$ pipe open at one end has length $0.8 \,m$. At the open end of the tube, a string $0.5 \,m$ long is vibrating in its $1^{\text{st}}$ overtone and resonates with the fundamental frequency of the pipe. If the tension in the string is $50 \,N$, what is the mass of the string (in $\,g$)? (Speed of sound $= 320 \,m/s$)

$A$ massless rod of length $L$ is suspended by two identical strings $AB$ and $CD$ of equal length. $A$ block of mass $m$ is suspended from point $O$ such that $BO$ is equal to $x$. Further,it is observed that the frequency of the $1^{st}$ harmonic in $AB$ is equal to the $2^{nd}$ harmonic frequency in $CD$. The value of $x$ is