The frequency of a tuning fork is $n \ Hz$ and the velocity of sound in air is $V \ m/s$. When the tuning fork completes $x$ vibrations,the distance traveled by the wave is:

  • A
    $\frac{V}{xn}$
  • B
    $\frac{Vn}{x}$
  • C
    $\frac{xV}{n}$
  • D
    $\frac{x}{Vn}$

Explore More

Similar Questions

The wavelength of one wave is $99 \ cm$ and that of another is $100 \ cm$. If the speed of sound is $396 \ m/s$,the number of beats heard per second is:

What is beat frequency?

During the superposition of two waves of nearly equal frequencies,the beat frequency is defined as the:

$A$ set of $28$ tuning forks is arranged in an increasing order of frequencies. Each fork produces '$x$' beats per second with the preceding fork and the last fork is an octave of the first. If the frequency of the $12^{\text{th}}$ fork is $152 \text{ Hz}$,the value of '$x$' (number of beats per second) is:

Two waves of wavelength $2 \ m$ and $2.02 \ m$ respectively,moving with the same velocity,superimpose to produce $2$ beats per second. The velocity of the waves is $... \ m/s$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo