The frequency of an electromagnetic radiation | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The relationship between velocity of light $(c)$,frequency $(
u)$,and wavelength $(\lambda)$ is given by the formula: $c = 
u 	imes \lambda$. R

Vedclass · Accepted Answer

$1.5 	imes 10^2$

Vedclass · Answer

(C) The relationship between velocity of light $(c)$,frequency $(
u)$,and wavelength $(\lambda)$ is given by the formula: $c = 
u 	imes \lambda$. Rearranging the formula to solve for wavelength: $\lambda = \frac{c}{
u}$. Given: $c = 3 	imes 10^8 \ m \ s^{-1}$ and $
u = 2 	imes 10^6 \ Hz$. Substituting the values: $\lambda = \frac{3 	imes 10^8}{2 	imes 10^6} = 1.5 	imes 10^2 \ m$. Therefore,the correct option is $(C)$.

The frequency of an electromagnetic radiation is $2 \times 10^6 \ Hz$. What is its wavelength in metres? (Velocity of light $= 3 \times 10^8 \ m \ s^{-1}$)

Similar Questions

What is light?

Describe the electromagnetic spectrum.

Explain the dual behavior of electromagnetic radiation.

Find the ratio of energy for radiations having $6000 \ \mathring{A}$ and $4000 \ \mathring{A}$ wavelength.
$(h = 6.62 \times 10^{-34} \ J \ s, c = 3 \times 10^8 \ m \ s^{-1})$

If the energies of two photons are in the ratio of $3:2$,their wavelengths will be in the ratio of

Vedclass Test Series

Exam Paper Generator

Online Exam Module