(B) For an open organ pipe,the fundamental frequency is given by $n_{open} = \frac{v}{2L} = 320 \ Hz$.For a closed organ pipe of the same length $L$,t

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(B) For an open organ pipe,the fundamental frequency is given by $n_{open} = \frac{v}{2L} = 320 \ Hz$.For a closed organ pipe of the same length $L$,the fundamental frequency is given by $n_{closed} = \frac{v}{4L}$.Comparing the two expressions,we get $n_{closed} = \frac{1}{2} \times n_{open}$.Substituting the given value: $n_{closed} = \frac{1}{2} \times 320 \ Hz = 160 \ Hz$.

Class 11 Physics Waves and Sound Longitudinal Stationary Waves (Organ Pipes) and Resonance Tube

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The frequency of the fundamental tone in an open organ pipe of length $0.48 \ m$ is $320 \ Hz$. The speed of sound is $320 \ m/s$. What will be the frequency of the fundamental tone in a closed organ pipe of the same length?

A
$153.8$
B
$160.0$
C
$320.0$
D
$143.2$

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Waves and Sound

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Longitudinal Stationary Waves (Organ Pipes) and Resonance Tube

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The frequency of the fundamental tone in an open organ pipe of length $0.48 \ m$ is $320 \ Hz$. The speed of sound is $320 \ m/s$. What will be the frequency of the fundamental tone in a closed organ pipe of the same length?

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The fundamental frequency of a pipe is $100 \ Hz$ and the next two frequencies are $300 \ Hz$ and $500 \ Hz$. Then:

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