The fringe widths are found to be $\omega_1$ and $\omega_2$ respectively if a Young's double slit experiment is performed in media of refractive indices $n_1$ and $n_2$ respectively. The correct statement is:

  • A
    $\omega_1 > \omega_2$ if $n_1 > n_2$
  • B
    $\omega_1 > \omega_2$ if $n_1 < n_2$
  • C
    $\omega_1 = \omega_2$ if $n_1 < n_2$
  • D
    $\frac{\omega_1}{\omega_2} = \frac{n_1}{n_2}$

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