The general solution of $\tan 3x = 1$ is
- A$x = n\pi, n \in Z$
- B$x = n\left(\frac{\pi}{3}\right) + \frac{\pi}{12}, n \in Z$
- C$x = n\pi + \frac{\pi}{4}, n \in Z$
- D$x = n\pi \pm \frac{\pi}{4}, n \in Z$
Explore More
Similar Questions
The principal solutions of $\tan 3 \theta = -1$ are
If $\tan (\cot x) = \cot (\tan x),$ then $\sin 2x =$
Difficult
View SolutionIf $4(\sin 2x \sin 4x + \sin^2 x) = 3$,then $x =$
The number of solutions of the equation $\sin 2x - 2 \cos x + 4 \sin x = 4$ in the interval $[0, 5\pi]$ is
DifficultJEE MAIN 2013
View SolutionNumber of solutions of the equation $\sin x - \sin 2x + \sin 3x = 2 \cos^2 x - 2 \cos x$ in the interval $(0, \pi)$ is
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo