The general solution of the differential equation $\frac{dy}{dx} + \frac{y}{x} = x^2 + 5$ is ....
- A$xy = \frac{x^4}{4} + \frac{5x^2}{2} + c$
- B$xy = \frac{x^4}{4} - \frac{5x^2}{2} + c$
- C$y = \frac{x^4}{4} + \frac{5x^2}{2} + c$
- D$y = \frac{x^4}{4} - \frac{5x^2}{2} + c$
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