The geometry of Ni(CO)_4 and Ni(PPh_3)_2Cl_2 | vedclass

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(D) In $Ni(CO)_4$,the oxidation state of $Ni$ is $0$. The configuration is $3d^8 4s^2$. Due to the strong field ligand $CO$,electrons pair up,resultin

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Both tetrahedral

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(D) In $Ni(CO)_4$,the oxidation state of $Ni$ is $0$. The configuration is $3d^8 4s^2$. Due to the strong field ligand $CO$,electrons pair up,resulting in $sp^3$ hybridization,which gives a tetrahedral geometry.In $Ni(PPh_3)_2Cl_2$,the oxidation state of $Ni$ is $+2$. The configuration is $3d^8$. $PPh_3$ is a bulky ligand,and $Cl^-$ is a weak field ligand. This complex also undergoes $sp^3$ hybridization,resulting in a tetrahedral geometry.Therefore,both complexes are tetrahedral.

The geometry of $Ni(CO)_4$ and $Ni(PPh_3)_2Cl_2$ are

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