The given figure shows the Maxwell distributi | vedclass

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(D) According to the Maxwell-Boltzmann distribution, as the temperature of a gas increases, the most probable speed $(u_{mp})$ increases, and the peak

Vedclass · Accepted Answer

$T_2 > T_3 > T_1$

Vedclass · Answer

(D) According to the Maxwell-Boltzmann distribution, as the temperature of a gas increases, the most probable speed $(u_{mp})$ increases, and the peak of the distribution curve shifts to the right and flattens.In the given figure, the peak for $T_2$ is at the highest speed, followed by $T_3$, and then $T_1$.Therefore, the most probable speed follows the order $u_{mp}(T_2) > u_{mp}(T_3) > u_{mp}(T_1)$.Since $u_{mp} = \sqrt{\frac{2RT}{M}}$, it implies that $u_{mp} \propto \sqrt{T}$.Thus, the correct order of temperature is $T_2 > T_3 > T_1$.

The given figure shows the Maxwell distribution of molecular speeds of a gas at three different temperatures $T_1$, $T_2$ and $T_3$. The correct order of temperature is

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