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(C) In the saturation region, the collector-emitter voltage $V_{CE}$ is approximately $0 \, V$.From the output loop circuit:$V_{CC} = I_C R_{out} + V_

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$8.2$

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(C) In the saturation region, the collector-emitter voltage $V_{CE}$ is approximately $0 \, V$.From the output loop circuit:$V_{CC} = I_C R_{out} + V_{CE}$Since $V_{CE} = 0 \, V$ at saturation:$3 = I_C (200)$$I_C = \frac{3}{200} = 0.015 \, A = 15 \, mA$Using the relation $\beta = \frac{I_C}{I_B}$, we find the base current $I_B$ required for saturation:$I_B = \frac{I_C}{\beta} = \frac{15 	imes 10^{-3}}{200} = 75 	imes 10^{-6} \, A = 75 \, \mu A$Now, applying Kirchhoff's Voltage Law $(KVL)$ to the input loop:$V_{BB} = I_B R_{in} + V_{BE}$$V_{BB} = (75 	imes 10^{-6} \, A)(100 	imes 10^3 \, \Omega) + 0.7 \, V$$V_{BB} = 7.5 \, V + 0.7 \, V = 8.2 \, V$Thus, the required value of $V_{BB}$ is $8.2 \, V$.

The given transistor operates in the saturation region. What should be the value of $V_{BB}$ (in $Volt$)?
$(R_{out} = 200 \, \Omega, R_{in} = 100 \, k\Omega, V_{CC} = 3 \, V, V_{BE} = 0.7 \, V, \beta = 200)$

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The given transistor operates in the saturation region. What should be the value of $V_{BB}$ (in $Volt$)?$(R_{out} = 200 \, \Omega, R_{in} = 100 \, k\Omega, V_{CC} = 3 \, V, V_{BE} = 0.7 \, V, \beta = 200)$