The graph AB shown in the figure is a plot of | vedclass

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(B) The relationship between the Celsius $(C)$ and Fahrenheit $(F)$ temperature scales is given by the formula:$\frac{C}{5} = \frac{F - 32}{9}$Rearran

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Slope of line $AB$ is $5/9$

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(B) The relationship between the Celsius $(C)$ and Fahrenheit $(F)$ temperature scales is given by the formula:$\frac{C}{5} = \frac{F - 32}{9}$Rearranging this equation to express $C$ in terms of $F$:$C = \frac{5}{9}F - \frac{160}{9}$Comparing this with the standard equation of a straight line,$y = mx + c$,where $y$ is the temperature in Celsius,$x$ is the temperature in Fahrenheit,and $m$ is the slope:$y = \left(\frac{5}{9}\right)x - \frac{160}{9}$Thus,the slope $m$ of the line $AB$ is $5/9$.

The graph $AB$ shown in the figure is a plot of the temperature of a body in degrees Celsius $(C)$ versus degrees Fahrenheit $(F)$. Then:

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