(C) For an $s$-orbital,the probability density $|\psi|^2$ is maximum at the nucleus $(r=0)$.The number of radial nodes is given by the formula $n-l-1$

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(C) For an $s$-orbital,the probability density $|\psi|^2$ is maximum at the nucleus $(r=0)$.The number of radial nodes is given by the formula $n-l-1$.For the $2s$ orbital,the number of radial nodes is $2-0-1 = 1$.The graph shows one radial node (where the curve touches the $r$-axis),which is characteristic of the $2s$ orbital.Therefore,the graph represents the $2s$ orbital.

Class 11 Chemistry Structure of Atom Quantum number, Electronic configuration and Shape of orbitals

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The graph between $|\psi|^2$ and $r$ (radial distance) is shown below. This represents

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$1s$ orbital
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$3s$ orbital
C
$2s$ orbital
D
$2p$ orbital

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Structure of Atom

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Quantum number, Electronic configuration and Shape of orbitals

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Which of the following sets of quantum numbers is correct for an electron in $4f$ orbital?

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In a given atom,no two electrons can have the same values for all the four quantum numbers. This is called:

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For an electron with quantum numbers $s = +1/2$ and $m_l = -1$,which of the following orbitals is not possible?

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In the ground state, an element has $13$ electrons in the $M$ shell. The element is

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How is the angular node determined? State the number of angular nodes for $s, p, d,$ and $f$ orbitals.

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The graph between $|\psi|^2$ and $r$ (radial distance) is shown below. This represents

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Which of the following sets of quantum numbers is correct for an electron in $4f$ orbital?

In a given atom,no two electrons can have the same values for all the four quantum numbers. This is called:

For an electron with quantum numbers $s = +1/2$ and $m_l = -1$,which of the following orbitals is not possible?

In the ground state, an element has $13$ electrons in the $M$ shell. The element is

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