The graph in the figure represents:

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(A) For a simple harmonic oscillator,the displacement is given by $x(t) = A \sin(\omega t + \phi)$.The velocity is given by $v(t) = \frac{dx}{dt} = A\

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Motion of a simple pendulum starting from the mean position.

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(A) For a simple harmonic oscillator,the displacement is given by $x(t) = A \sin(\omega t + \phi)$.The velocity is given by $v(t) = \frac{dx}{dt} = A\omega \cos(\omega t + \phi)$.From the given graph,at $t = 0$,the velocity $v(0)$ is maximum (positive peak).If the pendulum starts from the mean position $(x=0)$,the velocity is maximum at $t=0$,which matches the graph.If the pendulum starts from the extreme position $(x=A)$,the velocity is $0$ at $t=0$,which does not match the graph.Therefore,the graph represents the motion of a simple pendulum starting from the mean position.

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