The graph of the linear equation y = x passes | vedclass

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Question

(A) The given linear equation is $y = x$.For a point $(x, y)$ to lie on the graph of this equation,the $x$-coordinate must be equal to the $y$-coordin

Vedclass · Accepted Answer

$(1, 1)$

Vedclass · Answer

(A) The given linear equation is $y = x$.For a point $(x, y)$ to lie on the graph of this equation,the $x$-coordinate must be equal to the $y$-coordinate.Checking the options:$A$: $(1, 1)$ where $x = 1$ and $y = 1$. Since $1 = 1$,the point $(1, 1)$ satisfies the equation $y = x$.$B$: $(0, 3/2)$ where $x = 0$ and $y = 1.5$. Since $0 
eq 1.5$,it does not lie on the line.$C$: $(3/2, -3/2)$ where $x = 1.5$ and $y = -1.5$. Since $1.5 
eq -1.5$,it does not lie on the line.$D$: $(-1/2, 1/2)$ where $x = -0.5$ and $y = 0.5$. Since $-0.5 
eq 0.5$,it does not lie on the line.Therefore,the graph passes through the point $(1, 1)$.

The graph of the linear equation $y = x$ passes through the point.

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