The graph of the polynomial p(x) = ax - b,whe | vedclass

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Question

(C) To find the point where the graph of the polynomial $p(x) = ax - b$ intersects the $X$-axis,we set $p(x) = 0$.Setting $ax - b = 0$ gives $ax = b$.

Vedclass · Accepted Answer

$(\frac{b}{a}, 0)$

Vedclass · Answer

(C) To find the point where the graph of the polynomial $p(x) = ax - b$ intersects the $X$-axis,we set $p(x) = 0$.Setting $ax - b = 0$ gives $ax = b$.Solving for $x$,we get $x = \frac{b}{a}$.Since the point lies on the $X$-axis,its y-coordinate is $0$.Therefore,the graph intersects the $X$-axis at the point $(\frac{b}{a}, 0)$.

The graph of the polynomial $p(x) = ax - b$,where $a \neq 0$ and $a, b \in R$,intersects the $X$-axis at which unique point?

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