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(D) For a thin lens,the magnification $m$ is given by $m = \frac{v}{f} - 1$,where $v$ is the image distance and $f$ is the focal length.This is a line

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$\frac {b}{c}$

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(D) For a thin lens,the magnification $m$ is given by $m = \frac{v}{f} - 1$,where $v$ is the image distance and $f$ is the focal length.This is a linear equation of the form $y = mx + c$,where the slope is $\frac{1}{f}$.From the graph,the slope is the change in magnification divided by the change in image distance:Slope $= \frac{\Delta m}{\Delta v} = \frac{c}{b}$.Since the slope is also equal to $\frac{1}{f}$,we have $\frac{1}{f} = \frac{c}{b}$.Therefore,the focal length is $f = \frac{b}{c}$.

The graph shows how the magnification $m$ produced by a thin lens varies with image distance $v$. What is the focal length of the lens used?

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