The graph shows the variation of voltage V ac | vedclass

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(A) The relationship between charge $Q$, capacitance $C$, and voltage $V$ is given by $Q = CV$, which can be rearranged as $V = (1/C)Q$.Comparing this

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Capacitor $A$ has higher capacitance.

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(A) The relationship between charge $Q$, capacitance $C$, and voltage $V$ is given by $Q = CV$, which can be rearranged as $V = (1/C)Q$.Comparing this with the equation of a straight line $y = mx$, where $y = V$ and $x = Q$, the slope $m$ of the graph is $1/C$.Therefore, $C = 1/(	ext{slope of the line})$.From the graph, the slope of line $A$ is smaller than the slope of line $B$ (since $V_A Since capacitance is inversely proportional to the slope, a smaller slope implies a larger capacitance.Thus, the capacitance of $A$ is greater than the capacitance of $B$.

The graph shows the variation of voltage $V$ across the plates of two capacitors $A$ and $B$ versus the charge $Q$ stored in them. Then:

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