The group of molecules having identical shape | vedclass

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(D) To determine the shape,we calculate the hybridization and number of lone pairs for each molecule in option $D$:$ClF_3$: Hybridization $= 3 + \frac

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$ClF_3, XeOF_2, XeF_3^+$

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(D) To determine the shape,we calculate the hybridization and number of lone pairs for each molecule in option $D$:$ClF_3$: Hybridization $= 3 + \frac{1}{2}[7 - 3] = 5$ $(sp^3d)$,with $2$ lone pairs,resulting in a $T$-shaped geometry.$XeOF_2$: Hybridization $= 3 + \frac{1}{2}[8 - 4] = 5$ $(sp^3d)$,with $2$ lone pairs,resulting in a $T$-shaped geometry.$XeF_3^+$: Hybridization $= 3 + \frac{1}{2}[8 - 3 - 1] = 5$ $(sp^3d)$,with $2$ lone pairs,resulting in a $T$-shaped geometry.Since all three molecules have $sp^3d$ hybridization and $2$ lone pairs,they all possess an identical $T$-shaped geometry.

The group of molecules having identical shape is

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