(B) For $A$,$t_{1/2} = 1 \ min$. After $4 \ min$ ($4$ half-lives),the fraction of $A$ remaining is $(1/2)^4 = 1/16$. Therefore,the fraction of $A$ dis

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) For $A$,$t_{1/2} = 1 \ min$. After $4 \ min$ ($4$ half-lives),the fraction of $A$ remaining is $(1/2)^4 = 1/16$. Therefore,the fraction of $A$ disintegrated is $1 - 1/16 = 15/16$. For $B$,$t_{1/2} = 2 \ min$. After $4 \ min$ ($2$ half-lives),the fraction of $B$ remaining is $(1/2)^2 = 1/4$. Therefore,the fraction of $B$ disintegrated is $1 - 1/4 = 3/4$. The ratio of disintegrated weights of $A$ and $B$ is $(15/16) : (3/4) = 15/16 : 12/16 = 15:12 = 5:4$.

Class 12 Chemistry Nuclear Chemistry Rate of decay and Half-life

Difficult

The half-lives of two radioactive nuclides $A$ and $B$ are $1 \ min$ and $2 \ min$ respectively. Equal weights of $A$ and $B$ are taken separately and allowed to disintegrate for $4 \ min$. What will be the ratio of weights of $A$ and $B$ disintegrated?

TS EAMCET 2005 All TS EAMCET

AP EAMCET 2022 All AP EAMCET

A
$1:1$
B
$5:4$
C
$1:2$
D
$1:3$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Nuclear Chemistry

Subtopic

Rate of decay and Half-life

Previous Year

TS EAMCET 2005 Paper All TS EAMCET years →

Previous Year

AP EAMCET 2022 Paper All AP EAMCET years →

$A$ radioactive element has a half-life of $200 \ days$. The percentage of original activity remaining after $83 \ days$ is $....$ (Nearest integer).
(Given: $\text{antilog } 0.125 = 1.333$,$\text{antilog } 0.693 = 4.93$)

MediumJEE MAIN 2022

View Solution

If $8.0 \ g$ of a radioactive substance has a half-life of $10 \ hrs.$,the half-life of $2.0 \ g$ of the same substance is .......... $hr$.

Medium

View Solution

The unit of the decay constant for radioactive disintegration is:

MediumMHT CET 2011

View Solution

Given that a radioactive species decays according to the exponential law $N = N_0 e^{-\lambda t}$,the half-life of the species is:

Medium

View Solution

The half-life of $10 \ g$ of a radioactive substance is $10 \ days$. The half-life of $20 \ g$ of the same substance is .......... $days$.

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

The half-lives of two radioactive nuclides $A$ and $B$ are $1 \ min$ and $2 \ min$ respectively. Equal weights of $A$ and $B$ are taken separately and allowed to disintegrate for $4 \ min$. What will be the ratio of weights of $A$ and $B$ disintegrated?

Similar Questions

$A$ radioactive element has a half-life of $200 \ days$. The percentage of original activity remaining after $83 \ days$ is $....$ (Nearest integer).(Given: $\text{antilog } 0.125 = 1.333$,$\text{antilog } 0.693 = 4.93$)

If $8.0 \ g$ of a radioactive substance has a half-life of $10 \ hrs.$,the half-life of $2.0 \ g$ of the same substance is .......... $hr$.

The unit of the decay constant for radioactive disintegration is:

Given that a radioactive species decays according to the exponential law $N = N_0 e^{-\lambda t}$,the half-life of the species is:

The half-life of $10 \ g$ of a radioactive substance is $10 \ days$. The half-life of $20 \ g$ of the same substance is .......... $days$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$A$ radioactive element has a half-life of $200 \ days$. The percentage of original activity remaining after $83 \ days$ is $....$ (Nearest integer).
(Given: $\text{antilog } 0.125 = 1.333$,$\text{antilog } 0.693 = 4.93$)