The heat of combustion of methane is -800 kJ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The molar mass of methane $(CH_{4})$ is $16 \ g \ mol^{-1} = 16 	imes 10^{-3} \ kg \ mol^{-1}$.Given that the heat of combustion for $1 \ mol$ $(

Vedclass · Accepted Answer

$-20 \ kJ$

Vedclass · Answer

(C) The molar mass of methane $(CH_{4})$ is $16 \ g \ mol^{-1} = 16 	imes 10^{-3} \ kg \ mol^{-1}$.Given that the heat of combustion for $1 \ mol$ $(16 	imes 10^{-3} \ kg)$ of $CH_{4}$ is $-800 \ kJ$.To find the heat of combustion for $4 	imes 10^{-4} \ kg$ of $CH_{4}$,we use the unitary method:$\Delta H = \frac{-800 \ kJ}{16 	imes 10^{-3} \ kg} 	imes (4 	imes 10^{-4} \ kg)$$\Delta H = -800 	imes \frac{4 	imes 10^{-4}}{16 	imes 10^{-3}}$$\Delta H = -800 	imes \frac{4}{16} 	imes 10^{-1}$$\Delta H = -800 	imes 0.25 	imes 0.1 = -20 \ kJ$.

The heat of combustion of methane is $-800 \ kJ \ mol^{-1}$. What is the heat of combustion for $4 \times 10^{-4} \ kg$ of methane?

Similar Questions

The weight of calcium oxide formed by burning $20 \ g$ of calcium in excess oxygen is $.... \ g$

The Molarity $(M)$ of an aqueous solution containing $5.85 \ g$ of $NaCl$ in $500 \ mL$ water is :
(Given : Molar Mass $Na: 23$ and $Cl: 35.5 \ g \ mol^{-1}$ )

Calculate the amount of $CO_2$ gas produced when $32 \text{ g}$ of $CH_4$ is burned with a sufficient amount of oxygen. (Given: atomic weights of $C=12, O=16, H=1$) (in $\text{ g}$)

How many grams of iron are theoretically produced by the reduction of $1 \ kg$ of $Fe_2O_3$?

To obtain the maximum mass of $NO_2$ from a given mass of a mixture of $NH_3$ and $O_2$,the ratio of the mass of $NH_3$ to $O_2$ should be based on the reaction: $NH_3 + O_2 \longrightarrow NO_2 + H_2O$

Vedclass Test Series

Exam Paper Generator

Online Exam Module