The height above the surface of the earth where acceleration due to gravity becomes $\frac{g}{9}$ is ( $R$ is the radius of the earth,$g$ is the acceleration due to gravity at the surface).

  • A
    $2R$
  • B
    $\frac{R}{3}$
  • C
    $\frac{R}{\sqrt{2}}$
  • D
    $\sqrt{2} R$

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