The height of a cone is 9 , cm. The area of t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The formula for the volume of a cone is given by $V = \frac{1}{3} \pi r^2 h$,where $\pi r^2$ is the area of the base.Given,the area of the base $(

Vedclass · Accepted Answer

$4158$

Vedclass · Answer

(A) The formula for the volume of a cone is given by $V = \frac{1}{3} \pi r^2 h$,where $\pi r^2$ is the area of the base.Given,the area of the base $(A)$ = $1386 \, cm^2$ and the height $(h)$ = $9 \, cm$.Substituting these values into the formula:$V = \frac{1}{3} 	imes A 	imes h$$V = \frac{1}{3} 	imes 1386 	imes 9$$V = 1386 	imes 3$$V = 4158 \, cm^3$.Therefore,the volume of the cone is $4158 \, cm^3$.

The height of a cone is $9 \, cm$. The area of the base is $1386 \, cm^2$. Find its volume (in $cm^3$).

Similar Questions

Find the curved surface area and the total surface area of a hemisphere with a radius of $17.5 \, cm$.

Find the surface area of a sphere of radius $50\, cm$ $(\pi = 3.14)$ (in $cm^2$).

The diameter of a solid hemisphere is $21 \, cm$,then its volume is $\ldots \ldots \ldots \, cm^3$.

The total surface area of a closed cylinder is $748\, cm^2$. If its radius is $7\, cm$,find its height (in $cm$).

The radii of two cylinders are in the ratio of $2:3$ and their heights are in the ratio of $5:3$. The ratio of their volumes is

Vedclass Test Series

Exam Paper Generator

Online Exam Module