The highest occupied molecular orbital for Ne | vedclass

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Question

(D) The total number of electrons in $Ne_2$ is $10 + 10 = 20$.
The molecular orbital configuration for $Ne_2$ is: $(\sigma_{1s})^2, (\sigma^*_{1s})^2,

Vedclass · Accepted Answer

$\sigma^*_{2p}$

Vedclass · Answer

(D) The total number of electrons in $Ne_2$ is $10 + 10 = 20$.
The molecular orbital configuration for $Ne_2$ is: $(\sigma_{1s})^2, (\sigma^*_{1s})^2, (\sigma_{2s})^2, (\sigma^*_{2s})^2, \sigma_{2p_z}^2, \pi_{2p_x}^2, \pi_{2p_y}^2, (\pi^*_{2p_x})^2, (\pi^*_{2p_y})^2, (\sigma^*_{2p_z})^2$.
Counting the electrons: $2+2+2+2+2+2+2+2+2+2 = 20$.
The highest occupied molecular orbital $(HOMO)$ is the last orbital filled, which is $\sigma^*_{2p_z}$ (often denoted as $\sigma^*_{2p}$).

The highest occupied molecular orbital for $Ne_2$ is

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