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(A) The alkaline hydrolysis of tert-butyl bromide with aqueous alkali such as $NaOH$ or $KOH$ follows an $SN^1$ mechanism.This is a two-step process:S

Vedclass · Accepted Answer

transition state of $1^{st}$ step

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(A) The alkaline hydrolysis of tert-butyl bromide with aqueous alkali such as $NaOH$ or $KOH$ follows an $SN^1$ mechanism.This is a two-step process:Step $1$: $(CH_3)_3C-Br \rightarrow (CH_3)_3C^+ + Br^-$ (Slow,rate-determining step)Step $2$: $(CH_3)_3C^+ + OH^- \rightarrow (CH_3)_3C-OH$ (Fast step)In an energy profile diagram for a multi-step reaction,the highest peak corresponds to the transition state of the rate-determining step.Since the first step is the rate-determining step,the highest energy barrier (peak) in the energy profile diagram represents the transition state of the $1^{st}$ step.

The highest peak in the energy profile diagram for the mechanism of alkaline hydrolysis of tertiary butyl bromide represents:

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