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(B) The force per unit length on a current-carrying conductor in a magnetic field is given by the formula $f = \frac{F}{L} = I B \sin 	heta$.Here,the

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$3 	imes 10^{-5}$

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(B) The force per unit length on a current-carrying conductor in a magnetic field is given by the formula $f = \frac{F}{L} = I B \sin 	heta$.Here,the magnetic field $B = 3 	imes 10^{-5} \, T$ is directed from south to north.The current $I = 1 \, A$ flows from east to west.Since the direction of the current (east-west) is perpendicular to the direction of the magnetic field (south-north),the angle $	heta = 90^{\circ}$.Substituting the values into the formula:$f = 1 \, A 	imes (3 	imes 10^{-5} \, T) 	imes \sin(90^{\circ})$$f = 1 	imes 3 	imes 10^{-5} 	imes 1$$f = 3 	imes 10^{-5} \, N/m$.

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