The hybridisation and structure of XeF_6 is : | vedclass

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(B) $Xe$ has $8$ valence electrons.In $XeF_6$,$6$ electrons are involved in bonding with $6$ fluorine atoms,and $2$ electrons remain as a lone pair.St

Vedclass · Accepted Answer

$sp^3d^3,$ distorted octahedral

Vedclass · Answer

(B) $Xe$ has $8$ valence electrons.In $XeF_6$,$6$ electrons are involved in bonding with $6$ fluorine atoms,and $2$ electrons remain as a lone pair.Steric number = (Number of bond pairs) + (Number of lone pairs) = $6 + 1 = 7$.$A$ steric number of $7$ corresponds to $sp^3d^3$ hybridisation.Due to the presence of one lone pair,the geometry is distorted octahedral.

The hybridisation and structure of $XeF_6$ is :

Similar Questions

Explain the value of electron gain enthalpy of noble gases. Give reasons for your answer.

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$XeF_6$ is

Assertion $(A)$: Noble gases have very low boiling points.
Reason $(R)$: All noble gases have general electronic configuration of $ns^2 np^6$ (except $He$).

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