The hybridisation of the central atom of BF_3 | vedclass

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Question

(A) For $BF_3$: The central atom $B$ has $3$ valence electrons and forms $3$ bonds with $F$ atoms. Steric number $= 3 + 0 = 3$,which corresponds to $s

Vedclass · Accepted Answer

$sp^2, sp^2, sp$

Vedclass · Answer

(A) For $BF_3$: The central atom $B$ has $3$ valence electrons and forms $3$ bonds with $F$ atoms. Steric number $= 3 + 0 = 3$,which corresponds to $sp^2$ hybridisation.For $SnCl_2$: The central atom $Sn$ has $4$ valence electrons. It forms $2$ bonds with $Cl$ atoms and has $1$ lone pair. Steric number $= 2 + 1 = 3$,which corresponds to $sp^2$ hybridisation.For $HgCl_2$: The central atom $Hg$ has $2$ valence electrons and forms $2$ bonds with $Cl$ atoms. Steric number $= 2 + 0 = 2$,which corresponds to $sp$ hybridisation.Therefore,the correct sequence is $sp^2, sp^2, sp$.

The hybridisation of the central atom of $BF_3$,$SnCl_2$,and $HgCl_2$ respectively is:

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