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(D) The strength of a hydrogen bond depends on the electronegativity difference between the atoms involved and the charge density. Hydrogen bonds invo

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$F^{-}H...F$

Vedclass · Answer

(D) The strength of a hydrogen bond depends on the electronegativity difference between the atoms involved and the charge density. Hydrogen bonds involving ions (like $F^{-}...H-F$) are significantly stronger than neutral hydrogen bonds. The interaction $F^{-}H...F$ involves a fluoride ion $(F^{-})$ and a hydrogen fluoride molecule $(HF)$. This is a very strong hydrogen bond because the fluoride ion has a high negative charge density and the $H-F$ bond is highly polarized,leading to a very strong electrostatic attraction. Therefore,the strength follows the order $F^{-}H...F > F^{-}H...O > O^{-}H...F > O^{-}H...O$.

The hydrogen bond strength will be highest for

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