The hydrolysis products of the BrF_5 molecule | vedclass

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(B) The hydrolysis of interhalogen compounds like $BrF_5$ involves the reaction with water to form hydrohalic acid and an oxyacid of the halogen with

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$HF, HBrO_3$

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(B) The hydrolysis of interhalogen compounds like $BrF_5$ involves the reaction with water to form hydrohalic acid and an oxyacid of the halogen with a higher oxidation state.For $BrF_5$,the balanced chemical equation is: $BrF_5 + 3H_2O \rightarrow HBrO_3 + 5HF$.Here,$BrF_5$ reacts with $3$ moles of water to produce $1$ mole of bromic acid $(HBrO_3)$ and $5$ moles of hydrogen fluoride $(HF)$.Therefore,the products are $HF$ and $HBrO_3$.

The hydrolysis products of the $BrF_5$ molecule are given by the reaction: $BrF_5 + 3H_2O \rightarrow HBrO_3 + 5HF$. What are the products of this reaction?

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