The image of a candle flame formed by a lens | vedclass

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(A) Given that the image is formed on a screen,it must be a real image.For a real image,the magnification $m$ is negative. Given $m = -3$.We know that

Vedclass · Accepted Answer

$26.67$

Vedclass · Answer

(A) Given that the image is formed on a screen,it must be a real image.For a real image,the magnification $m$ is negative. Given $m = -3$.We know that $m = \frac{v}{u}$,where $v$ is the image distance and $u$ is the object distance.Since the image is on the other side of the lens,$v = +80 \, cm$.Using the magnification formula: $-3 = \frac{80}{u}$.Therefore,$u = -\frac{80}{3} \, cm \approx -26.67 \, cm$.The negative sign indicates that the object is placed in front of the lens at a distance of $26.67 \, cm$.The nature of the image is real and inverted,and the lens used is a convex lens.

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