For the reaction $A + B \xrightarrow{K} C$,identify the incorrect order of reaction indicated against the rate expression.
- A$\frac{d[C]}{dt} = K[A] \rightarrow 1$
- B$\frac{d[C]}{dt} = K[A][B] \rightarrow 2$
- C$\frac{-d[A]}{dt} = K[A][B]^0 \rightarrow 2$
- D$\frac{-d[A]}{dt} = K[A] \rightarrow 1$
Explore More
Similar Questions
When the concentration of a reactant,$A$,in a reaction $A \to \text{Products}$ is doubled,the rate of reaction increases seven times. The order of the reaction is between:
Medium
View SolutionThe value of $\frac{t_{0.875}}{t_{0.50}}$ for $n^{th}$ order reaction is
Difficult
View Solution$A$ complex reaction takes place in the following steps:
$NO_2Cl_{(g)} \longrightarrow NO_{2(g)} + Cl_{(g)}$ (slow)
$NO_2Cl_{(g)} + Cl_{(g)} \longrightarrow NO_{2(g)} + Cl_{2(g)}$ (fast)
Identify the rate law equation for this reaction.
$NO_2Cl_{(g)} \longrightarrow NO_{2(g)} + Cl_{(g)}$ (slow)
$NO_2Cl_{(g)} + Cl_{(g)} \longrightarrow NO_{2(g)} + Cl_{2(g)}$ (fast)
Identify the rate law equation for this reaction.
Write the formula for the rate of reaction $R \to P$ for zero-order and first-order reactions.
Easy
View SolutionThe time required for a definite fraction of a reaction to complete is inversely proportional to the initial concentration of the reactant. Find the order of the reaction.
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo