The incorrect order is

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(D) $1$. Covalent character: According to Fajan's rule,smaller cations have higher polarizing power. $Pb^{2+}$ is a pseudo-noble gas configuration ion

Vedclass · Accepted Answer

Boiling point : $CHCl_3 > CH_3Cl > CCl_4$

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(D) $1$. Covalent character: According to Fajan's rule,smaller cations have higher polarizing power. $Pb^{2+}$ is a pseudo-noble gas configuration ion,making it more polarizing than alkaline earth metal ions $(Ca^{2+}, Sr^{2+}, Ba^{2+})$. Thus,$PbCl_2$ is more covalent than the others. The order $PbCl_2 > CaCl_2 > SrCl_2 > BaCl_2$ is correct.$2$. Thermal stability: As the size of the halogen increases $(F $3$. Melting point: In ionic compounds,as the size of the anion increases,the lattice energy decreases,leading to a lower melting point. The order $KF > KCl > KBr > KI$ is correct.$4$. Boiling point: Boiling point depends on molecular mass and dipole-dipole interactions. $CHCl_3$ (polar,$M=119.5$),$CH_3Cl$ (polar,$M=50.5$),and $CCl_4$ (non-polar,$M=154$). The correct order of boiling points is $CCl_4 (350 \ K) > CHCl_3 (334 \ K) > CH_3Cl (249 \ K)$. Therefore,the given order $CHCl_3 > CH_3Cl > CCl_4$ is incorrect.

Similar Questions

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