The incorrect statement among the following i | vedclass

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(B) $1$. $\alpha-D$-glucose and $\beta-D$-glucose differ only in the configuration at the $C-1$ carbon (anomeric carbon),so they are anomers. Statemen

Vedclass · Accepted Answer

$\alpha-D$-glucose and $\beta-D$-glucose are enantiomers.

Vedclass · Answer

(B) $1$. $\alpha-D$-glucose and $\beta-D$-glucose differ only in the configuration at the $C-1$ carbon (anomeric carbon),so they are anomers. Statement $A$ is correct.$2$. Enantiomers are non-superimposable mirror images of each other. $\alpha-D$-glucose and $\beta-D$-glucose are diastereomers,not enantiomers. Statement $B$ is incorrect.$3$. Cellulose is a linear polymer of $\beta-D$-glucose units joined by $\beta-1,4$-glycosidic linkages. Statement $C$ is correct.$4$. The pentaacetate of glucose does not contain a free $-OH$ group at the $C-1$ position,meaning it cannot form an open-chain aldehyde structure to react with hydroxylamine $(NH_2OH)$. Statement $D$ is correct.Therefore,the incorrect statement is $B$.

List-$I$	List-$II$
$A$. $\alpha$-Glucose and $\alpha$-Galactose	$I$. Functional isomers
$B$. $\alpha$-Glucose and $\beta$-Glucose	$II$. Homologous
$C$. $\alpha$-Glucose and $\alpha$-Fructose	$III$. Anomers
$D$. $\alpha$-Glucose and $\alpha$-Ribose	$IV$. Epimers

The incorrect statement among the following is:

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