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(B) The reactions are as follows:$1. \ 2 Al + 6 HCl \longrightarrow 2 AlCl_3 + 3 H_2 \uparrow$ (Gas $'P'$ is $H_2$)$2. \ 2 Al + 2 NaOH + 2 H_2O \longr

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Gas $'P'$ and Gas $'Q'$ are different

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(B) The reactions are as follows:$1. \ 2 Al + 6 HCl \longrightarrow 2 AlCl_3 + 3 H_2 \uparrow$ (Gas $'P'$ is $H_2$)$2. \ 2 Al + 2 NaOH + 2 H_2O \longrightarrow 2 NaAlO_2 + 3 H_2 \uparrow$ (Gas $'Q'$ is $H_2$)From the reactions,we observe that both gases $'P'$ and $'Q'$ are hydrogen gas $(H_2)$.Therefore,the statement 'Gas $'P'$ and Gas $'Q'$ are different' is incorrect.

The incorrect statement regarding the above reactions is:
$Al_{(metal)} \xrightarrow[HCl]{(aq.)} 'X' + \text{Gas } 'P'$
$Al_{(metal)} \xrightarrow[NaOH (aq.)]{+ H_2O} 'Y' + \text{Gas } 'Q'$

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The incorrect statement regarding the above reactions is:$Al_{(metal)} \xrightarrow[HCl]{(aq.)} 'X' + \text{Gas } 'P'$$Al_{(metal)} \xrightarrow[NaOH (aq.)]{+ H_2O} 'Y' + \text{Gas } 'Q'$