The incorrect statement regarding the given s | vedclass

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Question

(A) The structure provided is $D$-glucose.$1$. $Br_2$ water is a mild oxidizing agent that oxidizes the $-CHO$ group to a $-COOH$ group,forming glucon

Vedclass · Accepted Answer

Can be oxidized to a dicarboxylic acid with $Br_2$ water

Vedclass · Answer

(A) The structure provided is $D$-glucose.$1$. $Br_2$ water is a mild oxidizing agent that oxidizes the $-CHO$ group to a $-COOH$ group,forming gluconic acid (a monocarboxylic acid),not a dicarboxylic acid. Thus,this statement is incorrect.$2$. Glucose exists primarily in cyclic hemiacetal forms in solution,where the concentration of the free aldehyde group is extremely low. Therefore,it does not give Schiff's test.$3$. $D$-glucose has $4$ chiral (asymmetric) carbon atoms (at $C_2, C_3, C_4, C_5$). This statement is correct.$4$. In aqueous solution,$D$-glucose exists in equilibrium with its $\alpha$ and $\beta$ pyranose cyclic forms. This statement is correct.

The incorrect statement regarding the given structure is:

Similar Questions

Compound $A$,$C_5H_{10}O_5$,gives a tetraacetate with $Ac_2O$ and oxidation of $A$ with $Br_2-H_2O$ gives an acid,$C_5H_{10}O_6$. Reduction of $A$ with $HI$ gives isopentane. The possible structure of $A$ is:

The letter '$D$' in $D$-glucose signifies

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