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(B) The reaction of $N,N$-dimethylaniline with $NaNO_2$ and $HX$ (nitrous acid) at low temperature $(0-5^{\circ}C)$ is an electrophilic aromatic subst

Vedclass · Accepted Answer

$'B'$ is $N$-nitroso ammonium compound

Vedclass · Answer

(B) The reaction of $N,N$-dimethylaniline with $NaNO_2$ and $HX$ (nitrous acid) at low temperature $(0-5^{\circ}C)$ is an electrophilic aromatic substitution reaction.$1$. The electrophile generated is the nitrosonium ion,$NO^{+}$.$2$. Since the $-N(CH_3)_2$ group is a strong ortho/para directing group,the electrophile $NO^{+}$ attacks the para position to form $p$-nitroso-$N,N$-dimethylaniline.$3$. Option $A$ is correct as $NO^{+}$ is the electrophile.$4$. Option $B$ is incorrect because the product is $p$-nitroso-$N,N$-dimethylaniline,not an $N$-nitroso ammonium compound (which would form with secondary amines).$5$. Option $C$ is correct as the reaction is performed at low temperatures to stabilize the nitrous acid and prevent side reactions.$6$. Option $D$ is correct as the major product is the $p$-nitroso derivative.

The incorrect statement regarding the reaction given below is:

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