The increasing order of basicity for the foll | vedclass

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(C) Basicity $\propto \frac{1}{	ext{Stability of conjugate base}}$.Stability order of the given carbanions:$(v)$ $CN^{-}$: The negative charge is on

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$(v) < (iii) < (ii) < (iv) < (i)$

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(C) Basicity $\propto \frac{1}{ ext{Stability of conjugate base}}$.Stability order of the given carbanions:$(v)$ $CN^{-}$: The negative charge is on the nitrogen atom (more electronegative) and it is also stabilized by the $-I$ effect of the triple bond. It is the most stable.$(iii)$ $HC \equiv C^{-}$: The negative charge is on an $sp$ hybridized carbon atom. It is more stable than $sp^2$ or $sp^3$ hybridized carbons.$(ii)$ $H_2C=CH-CH_2^{-}$: The negative charge is stabilized by resonance (delocalization).$(iv)$ $CH_3^{-}$: The negative charge is on an $sp^3$ hybridized carbon atom.$(i)$ $(CH_3)_3C^{-}$: The negative charge is on an $sp^3$ hybridized carbon atom,which is further destabilized by the $+I$ effect of three methyl groups. It is the least stable.Stability order: $(v) > (iii) > (ii) > (iv) > (i)$.Since Basicity $\propto \frac{1}{ ext{Stability}}$,the increasing order of basicity is: $(v) < (iii) < (ii) < (iv) < (i)$.

The increasing order of basicity for the following intermediates is (from weak to strong):
$(i)$ $(CH_3)_3C^{-}$
$(ii)$ $H_2C=CH-CH_2^{-}$
$(iii)$ $HC \equiv C^{-}$
$(iv)$ $CH_3^{-}$
$(v)$ $CN^{-}$

Similar Questions

The correct stability order for the following species is:
$(I)$ $o-CN-C_6H_4-CH_2^-$
$(II)$ $m-CN-C_6H_4-CH_2^-$
$(III)$ $p-CN-C_6H_4-CH_2^-$
$(IV)$ $C_6H_5-CH_2^-$
(Note: The image shows the structures of these carbanions.)

The central carbon atom of a free radical contains

Which of the following carbocations is expected to be most stable?

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The increasing order of basicity for the following intermediates is (from weak to strong):$(i)$ $(CH_3)_3C^{-}$$(ii)$ $H_2C=CH-CH_2^{-}$$(iii)$ $HC \equiv C^{-}$$(iv)$ $CH_3^{-}$$(v)$ $CN^{-}$