The increasing order of boiling points of the | vedclass

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(B) To determine the boiling point order,we analyze the intermolecular forces present in each molecule:$1$. $CH_3CH_2CH_3$ $(III)$: This is an alkane,

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$III < I < II < IV$

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(B) To determine the boiling point order,we analyze the intermolecular forces present in each molecule:$1$. $CH_3CH_2CH_3$ $(III)$: This is an alkane,which only has weak London dispersion forces. It has the lowest boiling point.$2$. $CH_3-O-CH_3$ $(I)$: This is an ether,which has weak dipole-dipole interactions. Its boiling point is higher than the alkane but lower than polar molecules with stronger interactions.$3$. $CH_3CHO$ $(II)$: This is an aldehyde,which has stronger dipole-dipole interactions due to the polar $C=O$ bond.$4$. $CH_3CH_2OH$ $(IV)$: This is an alcohol,which exhibits strong intermolecular hydrogen bonding. It has the highest boiling point among these.Thus,the increasing order of boiling points is $III < I < II < IV$.

Molecule	Label
$CH_3-O-CH_3$	$I$
$CH_3CHO$	$II$
$CH_3CH_2CH_3$	$III$
$CH_3CH_2OH$	$IV$

The increasing order of boiling points of the following is:
Molecule Label
$CH_3-O-CH_3$ $I$
$CH_3CHO$ $II$
$CH_3CH_2CH_3$ $III$
$CH_3CH_2OH$ $IV$

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The increasing order of boiling points of the following is:MoleculeLabel$CH_3-O-CH_3$$I$$CH_3CHO$$II$$CH_3CH_2CH_3$$III$$CH_3CH_2OH$$IV$