The increasing order of electron affinity for | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) First,identify the elements based on their electronic configurations:$I. 1s^2 2s^2 2p^6 3s^2 3p^5$ is Chlorine $(Cl)$,which has a high electron af

Vedclass · Accepted Answer

$II < IV < III < I$

Vedclass · Answer

(A) First,identify the elements based on their electronic configurations:$I. 1s^2 2s^2 2p^6 3s^2 3p^5$ is Chlorine $(Cl)$,which has a high electron affinity.$II. 1s^2 2s^2 2p^3$ is Nitrogen $(N)$,which has a half-filled $p$-orbital,making it very stable and resulting in a very low (near zero) electron affinity.$III. 1s^2 2s^2 2p^5$ is Fluorine $(F)$. Although $F$ is more electronegative than $Cl$,its electron affinity is slightly lower than $Cl$ due to high inter-electronic repulsion in the small $2p$ subshell.$IV. 1s^2 2s^2 2p^6 3s^1$ is Sodium $(Na)$,which is an alkali metal with a low electron affinity,but higher than Nitrogen $(N)$ because it can form a stable $3s^2$ configuration.Comparing these: Nitrogen $(II)$ has the lowest electron affinity due to its stable half-filled configuration. Sodium $(IV)$ is next. Fluorine $(III)$ is higher than Sodium,and Chlorine $(I)$ has the highest electron affinity among these.Therefore,the increasing order is $II < IV < III < I$.

The increasing order of electron affinity for the given electronic configurations of elements is:
$I. 1s^2 2s^2 2p^6 3s^2 3p^5$
$II. 1s^2 2s^2 2p^3$
$III. 1s^2 2s^2 2p^5$
$IV. 1s^2 2s^2 2p^6 3s^1$

Similar Questions

Which of the following is correct regarding the electron affinity of halogens?

Which of the following represents the correct order of increasing electron gain enthalpy with negative sign for the elements $O$,$S$,$F$ and $Cl$?

$A = 1s^2\, 2s^2\, 2p^4$,$B = 1s^2\, 2s^2\, 2p^5$,$C = 1s^2\, 2s^2\, 2p^6$. $A, B$ and $C$ are atoms/anions of the same element. Which one is correct? (One of $A/B/C$ is a neutral atom)

Among the following options, the correct trend in the electron gain enthalpy is

Arrange $N$,$S$,$O$ and $F$ in order of decreasing electron gain enthalpy.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The increasing order of electron affinity for the given electronic configurations of elements is:$I. 1s^2 2s^2 2p^6 3s^2 3p^5$$II. 1s^2 2s^2 2p^3$$III. 1s^2 2s^2 2p^5$$IV. 1s^2 2s^2 2p^6 3s^1$