The increasing order of stability of the foll | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The stability of free radicals is determined by resonance and inductive effects.Resonance provides greater stabilization than the inductive effect

Vedclass · Accepted Answer

$(CH_3)_2 \dot{C}H < (CH_3)_3 \dot{C} < (C_6H_5)_2 \dot{C}H < (C_6H_5)_3 \dot{C}$

Vedclass · Answer

(B) The stability of free radicals is determined by resonance and inductive effects.Resonance provides greater stabilization than the inductive effect.$(C_6H_5)_3 \dot{C}$ is the most stable due to resonance with three phenyl rings.$(C_6H_5)_2 \dot{C}H$ is the next most stable due to resonance with two phenyl rings.$(CH_3)_3 \dot{C}$ (tertiary alkyl radical) is more stable than $(CH_3)_2 \dot{C}H$ (secondary alkyl radical) due to the greater inductive effect and hyperconjugation.Thus,the increasing order of stability is: $(CH_3)_2 \dot{C}H < (CH_3)_3 \dot{C} < (C_6H_5)_2 \dot{C}H < (C_6H_5)_3 \dot{C}$.

The increasing order of stability of the following free radicals is:

Similar Questions

The lines $ax^2+2hxy+by^2=0$ are at right angles if

The displacement equations of two waves are given as $y_1 = 10 \sin(3\pi t + \pi/3)$ and $y_2 = 5(\sin 3\pi t + \sqrt{3} \cos 3\pi t)$. What is the ratio of their amplitudes?

The value of $\lambda$ with $|\lambda| < 16$ such that $2 x^2-10 x y+12 y^2+5 x+\lambda y-3=0$ represents a pair of straight lines,is

Find the potential difference across the $24\,\Omega$ resistor in the given circuit.

$A$ coil of wire of radius $r$ has $600$ turns and a self-inductance of $108 \ mH$. The self-inductance of a coil with the same radius and $500$ turns is (in $mH$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module