The increasing order of the acidity of the fo | vedclass

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Question

(A) The acidity of substituted benzoic acids depends on the electronic effects of the substituents at the para position.$1$. $-NO_2$ is a strong elect

Vedclass · Accepted Answer

$III < II < IV < I$

Vedclass · Answer

(A) The acidity of substituted benzoic acids depends on the electronic effects of the substituents at the para position.$1$. $-NO_2$ is a strong electron-withdrawing group ($-I$ and $-M$ effects),which significantly increases acidity.$2$. $-Cl$ is an electron-withdrawing group ($-I$ effect) but an electron-donating group ($+M$ effect). The $-I$ effect dominates,increasing acidity compared to benzoic acid.$3$. $-OH$ is an electron-donating group ($+M$ effect),which decreases acidity compared to benzoic acid.$4$. Benzoic acid $(II)$ is the reference.Comparing the substituents: $-NO_2$ (strongest electron-withdrawing) > $-Cl$ (weak electron-withdrawing) > $H$ (no effect) > $-OH$ (electron-donating).Therefore,the increasing order of acidity is $III < II < IV < I$.

The increasing order of the acidity of the following carboxylic acids is:

Similar Questions

The conversion of $CH_{3}CH_{2}COOH$ to the product shown below can be accomplished by:
$CH_{3}CH_{2}CH(OCH_{2}CH_{2}O)$

Product $(X)$ is

The final product $(III)$ obtained in the reaction sequence is:
$CH_3-CH_2-COOH$ $\xrightarrow{PCl_3} I$ $\xrightarrow{C_6H_6/AlCl_3} II$ $\xrightarrow{NH_2-NH_2/\text{base/heat}} III$

The product is:

The incorrect match is:

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