The input a.c. voltage of frequency $60 \,Hz$ is applied to a half-wave rectifier and also to a full-wave rectifier. The output frequency in the case of the half-wave rectifier and that in the case of the full-wave rectifier is respectively:
- A$120 \,Hz, 60 \,Hz$
- B$60 \,Hz, 120 \,Hz$
- C$60 \,Hz, 60 \,Hz$
- D$120 \,Hz, 120 \,Hz$
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The figure shows the current as a function of time at the output of a full-wave rectifier. The average value of this current is:
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View SolutionIf the output frequency of a full-wave rectifier is $100 \text{ Hz}$, then the input frequency will be . . . . . . . (in $\text{ Hz}$)
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What will be the output waveform for the rectifier shown in the figure?
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View SolutionMatch List-$I$ with List-$II$:
List-$I$ List-$II$ $(a)$ Rectifier $(i)$ Used for stepping up or stepping down the $\text{A.C.}$ voltage $(b)$ Stabilizer $(ii)$ Used to convert $\text{A.C.}$ voltage into $\text{D.C.}$ voltage $(c)$ Transformer $(iii)$ Used to remove any ripple in the rectified output voltage $(d)$ Filter $(iv)$ Used for constant output voltage
| List-$I$ | List-$II$ |
| $(a)$ Rectifier | $(i)$ Used for stepping up or stepping down the $\text{A.C.}$ voltage |
| $(b)$ Stabilizer | $(ii)$ Used to convert $\text{A.C.}$ voltage into $\text{D.C.}$ voltage |
| $(c)$ Transformer | $(iii)$ Used to remove any ripple in the rectified output voltage |
| $(d)$ Filter | $(iv)$ Used for constant output voltage |
Medium
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