The input signal given to a $C.E.$ amplifier having a voltage gain of $126$ is $V_i = 2 \cos \left(12 t + \frac{\pi}{3}\right)$. The corresponding output signal will be

The input signal given to a $CE$ amplifier having a voltage gain of $150$ is $V_{in} = 2 \cos(15t + \frac{\pi}{3}) \text{ V}$. The corresponding output signal will be:

In a common emitter transistor,the current gain is $80$. What is the change in collector current,when the change in base current is $250 \ \mu A$?

For a given transistor amplifier circuit in $CE$ configuration with $V_{CC} = 1 \text{ V}$,$R_c = 1 \text{ k}\Omega$,$R_b = 100 \text{ k}\Omega$,and $\beta = 100$,the value of the base current $I_b$ is:

$A$ $n-p-n$ transistor is connected in common-emitter configuration in which the collector supply is $8\, V$ and the voltage drop across the load resistance of $800\,\Omega$ connected in the collector circuit is $0.8\, V$. If the current amplification factor $\alpha$ is $25/26$,the collector-emitter voltage $V_{CE}$ and the base current $I_B$ will be:

In an $NPN$ transistor,the collector current is $10\, mA$. If $90\%$ of the electrons emitted reach the collector,then: