The instantaneous values of current and poten | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The instantaneous current is $i = \sin \omega t$,so the peak current $i_0 = 1 \ A$.The instantaneous potential difference is $E = 100 \cos \omega

Vedclass · Accepted Answer

$\frac{1}{\sqrt{2}}$

Vedclass · Answer

(B) The instantaneous current is $i = \sin \omega t$,so the peak current $i_0 = 1 \ A$.The instantaneous potential difference is $E = 100 \cos \omega t = 100 \sin(\omega t + \frac{\pi}{2})$.Comparing this with the standard form $E = E_0 \sin(\omega t + \phi)$,the phase difference between voltage and current is $\phi = \frac{\pi}{2}$.The wattless current is the component of the current that is $90^\circ$ out of phase with the voltage,given by $i_w = i \sin \phi$.The $r.m.s.$ value of the wattless current is $I_{w,rms} = \frac{i_0}{\sqrt{2}} \sin \phi$.Substituting the values: $I_{w,rms} = \frac{1}{\sqrt{2}} \sin(\frac{\pi}{2}) = \frac{1}{\sqrt{2}} 	imes 1 = \frac{1}{\sqrt{2}} \ A$.

The instantaneous values of current and potential difference in an alternating circuit are $i = \sin \omega t$ and $E = 100 \cos \omega t$ respectively. The $r.m.s.$ value of the wattless current (in $A$) in the circuit is:

Similar Questions

In an $ac$ circuit with voltage $V$ and current $I$,the power dissipated is

In an $AC$ circuit,$V$ and $I$ are given by $V = 150 \sin(150t) \, V$ and $I = 150 \sin(150t + \frac{\pi}{3}) \, A$. The power dissipated in the circuit is $W$.

In an $ac$ circuit,the current is given by $i = 5 \sin \left( 100 t - \frac{\pi}{2} \right)$ and the $ac$ potential is $V = 200 \sin (100 t) \text{ volts}$. Then the power consumption is $....... \text{ watts}$.

Define the power for $AC$ circuit. Obtain an equation of average power for $L-C-R$ series $AC$ circuit.

Current in the circuit is wattless, if

Vedclass Test Series

Exam Paper Generator

Online Exam Module