The integrated rate equation is $Rt = \log C_0 - \log C_t$. The straight line graph is obtained by plotting

  • A
    $time \ v/s \ \log C_t$
  • B
    $\frac{1}{time} \ v/s \ C_t$
  • C
    $time \ v/s \ C_t$
  • D
    $\frac{1}{time} \ v/s \ \frac{1}{C_t}$

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Similar Questions

For a first-order reaction,the time taken for the concentration of the reactant to reach $3/4$ of its initial value is $t_{1/4}$. If the rate constant for the reaction is $K$,then $t_{1/4}$ can be expressed as: (in $/K$)

Which of the following is a first-order reaction?

For a certain first order reaction,$32 \%$ of the reactant is left after $570 \ s$. The rate constant of this reaction is ........... $\times 10^{-3} \ s^{-1}$. (Round off to the Nearest Integer).
$[$Given: $\log_{10} 2 = 0.301, \ln 10 = 2.303]$

$A$ first-order reaction takes $69.3 \ min$ to complete $50\%$ of the reaction. How much time (in $min$) will it take to complete $80\%$ of the reaction?

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View Solution

For a first order reaction,$A \to P$,$t_{1/2}$ (half-life) is $10 \ days$. The time required for $\frac{1}{4}$ conversion of $A$ (in days) is: $(\ln 2 = 0.693, \ln 3 = 1.1)$.

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